FWHM evaluation
600 nm
700 nm
Set this average as
100%
100 % (full max.)
Divide 100 % by 2
gen
(half max.)
erage
t ra
50%
av
rge
ta
Obtain 1
tain
Obtain 2
at 50%
Ob
at 50%
within
0%
Ex. 1 =
Ex. 2 =
FWHM = 712
573 nm
712 nm
573 = 139 nm
Supportive Information for Homework 1, PME 5443, Mar. 15, 2015
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